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6x^2-2.4=0
a = 6; b = 0; c = -2.4;
Δ = b2-4ac
Δ = 02-4·6·(-2.4)
Δ = 57.6
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{57.6}}{2*6}=\frac{0-\sqrt{57.6}}{12} =-\frac{\sqrt{}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{57.6}}{2*6}=\frac{0+\sqrt{57.6}}{12} =\frac{\sqrt{}}{12} $
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